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## Kinematics JEE Chapterwise Analysis, Weightage and Overview

Kinematics is an important portion in mechanics as far as the marks are concern it is considered as a high scoring topic in IIT JEE, it contain a very less syllabus to covered but can give you many questions to score. Newton’s Laws of Motion, and Work Power and Energy are the most important topics you can consider. .

2010 | 2011 | 2012 | 2013 | 2014 | 2015 | 2016 | 2017 | 2018 | 2019 | 2020 | |

Kinematics JEE | 4 | 3 | 2 | 1 | 3 | 2 | 0 | 0 | 2 | 2 | 5 |

### List of important topics in Kinematics JEE

- Scalars and vectors
- Speed, velocity and acceleration
- Position - time, velocity - time graphs
- Relative velocity
- Motion under gravity
- Motion in a plane
- Projectile motion

### Kinematics JEE Syllabus

- Distance and Displacement, Some Conceptual Points, Average speed and Average velocity, Instantaneous Velocity, Average Acceleration and Instantaneous Acceleration, Some Important Point, Problem Solving Strategy.
- Motion in two or Three Dimension, Discussion, Motion under Gravity, Discussion. Graphs. Velocity of Approach. Projectile Motion. Motion in vertical direction, co-ordinates and velocity components of projectile. Projectile Motion in Inclined Plane, up the plane, Time of Flight, Range, Down the Plane.
- Relative Motion, (a) Minimum Distance Between Two Bodies In Motion, (b) River-Boat Problems, (i) Condition When The Boatman Crosses The River In Shortest Interval Of Time, (ii) Condition when the boatman wants to reach point B, i.e., at a point just opposite from where he Started, (c) Aircraft Wind Problems, (d) Rain problems. Aircraft Wind Problems, Rain Problems.

### Download Kinematics JEE Notes

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### Kinematics JEE Test Series 2022,2023,2024

List of FREE Tests | ||
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**Q. **I can't remember the difference between force impulse and impulse of force........please give me a trick to remember it.....?

Impulse is not a property of a particle rather it is a measure of the degree to which an external force changes the particle’s momentum.

The product of average force and the time it is exerted is called the impulse of force. Impulse of force can be extracted and found to be equal to the change in momentum of an object provided the mass is constant.

**Q. **Please can u explain me the concept of instantaneous velocity?

Instantaneous velocity-The velocity of an object at a given instant of time is called its instantaneous velocity. When a body is moving with uniform velocity, its instantaneous velocity = average velocity = uniform velocity.

**Q. **What is instantaneous velocity.?

The velocity of an object at a given instant of time is called its instantaneous velocity. When a body is moving with uniform velocity, its instantaneous velocity = average velocity = uniform velocity.

**Q. **two particles are moving along two straight lines in the same plane with same speed equal to 20m/sec the angle between the two lines is 60 degree and the intersection point is o at a certain moment the two particles are located at distance of 3m and 4m from o and are moving towards o subsequently, the shortest distance between them will be what? explain in brief please?

At time t=0, the first particle is 300 cm from O and moving toward O at a velocity of 20 m/s.

The distance of this particle to O as a function of time is:

A = 300 - 20t

At time t=0, the second particle is 400 cm from O and moving toward O at a velocity of 20 m/s.

The distance of this particle to O as a function of time is:

B = 400 - 20t

The distance between the 2 particles can be found using the cosine rule

C² = A² + B² - 2∙A∙B∙cos(60)

C² = (300 - 20t)² + (400 - 20t)² - 2∙(300 - 20t)∙(400 - 20t)∙cos(60)

C² = (400t² - 12000t + 90000) + (400t² - 16000t + 160000) - (400t² - 14000t + 120000)

C² = 400t² - 14000t + 130000

C = √(400t² - 14000t + 130000)

Now you need to find t such that C will be minimized.

To simplify things a bit, you must realize one important thing:

If C is minimized at a certain t, then also C² wil be minimized at that t.

So instead of finding the first derivative of C (which is a square root, so a lot of work) you can simply find the first derivative of of C² (a quadratic expression, which is a lot less work)

C² = 400t² - 14000t + 130000

(C²) ' = 800t - 14000

800t - 14000 = 0

t = 17.5 s

At time t = 17.5 s the distance between the 2 particles is minimized.

The distance at that time will be:

C = √(400∙17.5² - 14000∙17.5 + 130000)

C = √7500

C = 86.6 m

**Q. **A cart is moving horizontally along a straight line with constant speed = 30m/s. A particle is to be fired vertically upwards from the moving cart in such a way that it returns to the cart at the same point from where it was projected after the cart has moved 80m . At what speed( relative to the car) must the projectile be fired??

cart verlocity is uniform so vertical velocity be any.