x and y are the sides of two squares such that y = x – x2. Find the rate of change of the area of the second square with respect to the first square.
None of these
iven x and y are sides of two squares thus the area of two squares are x2and y2
Where the given curve is,
y = x – x2
The rate of change of the area of second square with respect to first square is (2x2 – 3x + 1).
If the displacement of a particle is given by Find the velocity and acceleration at t = 4 second.
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The tangent represented by the graph of the function y = f (x) at the point with abscissa x = 1 form an angle π/6 and at the point x = 2 an angle of π/3 and at the point x = 3 an angle π/4. Then find the value of,
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Find the acute angle between the curves y = | x2 – 1| and y = | x2 – 3 | at their points of intersection when x > 0.
If the relation between subnormal SN and subtangent ST at any point S on the curve; by2 = (x + a)3 is p(SN) = q(ST)2, then find the value of p/q.
in which interval
If f (x) = xα log x and f (0) = 0, then the value of ‘α’ for which Rolle’s theorem can be applied in [0, 1] is: