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Solution

Correct option is

SIMILAR QUESTIONS

Q1

Q5

If tan α is equal to the integral solution of the inequality 4x2 – 16x + 15 < 0 and cos β is equal to the slope of the bisector of the first quadrant, then sin (α + β) sin (α – β) is equal to

Q6

0, then the value of tan x tan y  tan z  tan t is equal to

Q7

is equal to

Q8

If A and B are acute positive angles which satisfy the equalities  then

A + 2B is equal to

Q10

then tan x, tan y, tan z are in.