If tan α is equal to the integral solution of the inequality 4x2 – 16x + 15 < 0 and cos β is equal to the slope of the bisector of the first quadrant, then sin (α + β) sin (α – β) is equal to
0, then the value of tan x tan y tan z tan t is equal to
is equal to
If A and B are acute positive angles which satisfy the equalities then
A + 2B is equal to
then tan x, tan y, tan z are in.
are in A.P. whose common difference is α, then the value of