Question

 and x = 2, then

 

Solution

Correct option is

a = 2, b = 1/2

We have y’ = a/x + 2bx + 1 and y’ (–1) = 0 and y’ (2) = 0

 ∴  –a – 2b + 1 = 0

and   a /2 + 4b + 1 = 0

 ⇒ a /2 – 2 a + 2 + 1 = 0

Hence a = 2 and b = –1/2.

SIMILAR QUESTIONS

Q2

The equation e 1 + x – 2 = 0 as 

Q3

The function f satisfying 

Q4

Suppose f is differentiable on R and a ≤ f’(x) ≤ b for all x ∈ R where ab> 0. If f (0) = 0, then

Q5

The minimum value of (x) = 

Q6

, for every real number, then minimum value of f

Q7

The image of the interval [–1, 3] under the maping f(x) = 4x3 – 12x is.

Q8

The difference between the greatest and least values of the function