Discus The Position Of The Points (1, 2) And (6, 0) With Respect To The Circle.                  x2 + y2 – 4x + 2y – 11 = 0   

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Question

 

Discus the position of the points (1, 2) and (6, 0) with respect to the circle.

                 x2 + y2 – 4x + 2y – 11 = 0   

Solution

Correct option is

(1, 2) inside & (6, 0) outside

 

  

      

  

And for the point (6, 0)

        

             

           = 36 – 35 = 1  

    

Hence the point (1, 2) lies inside the circle and the point (6, 0) lies outside the circle. 

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