Discuss The Position Of The Points (1, 2) And (6, 0) With Respect To The Circle                           x2 + y2 – 4x +2y – 11 = 0.

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Question

 

Discuss the position of the points (1, 2) and (6, 0) with respect to the circle

                          x2 + y2 – 4x +2y – 11 = 0.

Solution

Correct option is

(1, 2) is inside & (6, 0) is outside

 

Let S ≡ x2 + y2 – 4x + 2y – 11 = 0 for the point (1, 2)

      

        

and for the point (6, 0)

      

           

           

∴       S2 > 0

Hence the point (1,2) lies inside the circle and the point (6, 0) lies outside the circle.

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