Question

 

Discuss the position of the points (1, 2) and (6, 0) with respect to the circle

                          x2 + y2 – 4x +2y – 11 = 0.

Solution

Correct option is

(1, 2) is inside & (6, 0) is outside

 

Let S ≡ x2 + y2 – 4x + 2y – 11 = 0 for the point (1, 2)

      

        

and for the point (6, 0)

      

           

           

∴       S2 > 0

Hence the point (1,2) lies inside the circle and the point (6, 0) lies outside the circle.

SIMILAR QUESTIONS

Q1

Find the equation of the circle which passes through the points (4, 1), (6, 5) and has its centre on the line 4x + y = 16.

Q2

Find the equation of the circle passing through the three non-collinear points (1, 1), (2, –1) and (3, 2).

Q3

Show that the four points (1, 0), (2, –7), (8, 1) and (9, –6) are concyclic.

Q4

Find the equation of the circle whose diameter is the line joining the points (–4, 3) and (12, –1). Find also the intercept made by it on y-axis.

Q5

Find the equation of the circle which touches the axis of y at a distance of 4 units from the origin and cuts the intercept of 6 units from the axis of x.

Q6

Find the equation of the circle which passes through the origin and makes intercepts of length a and b on the x and y axes respectively.

Q7

Find the equation of the circle which touches the axes and whose centre lies on the line x – 2y = 3.

Q8

A circle of radius 2 lies in the first quadrant and touches both the axes of co-ordinates. Find the equation of the circle with centre at (6, 5) and touching the above circle externally.

Q9

A circle of radius 5 units touches the co-ordinates axes in first quadrant. If the circle makes one complete roll on x-axis along the positive direction of x-axis, find its equation in the new position.

Q10

 

Find the shortest and largest distance from the point (2, –7) to the circle 

                   x2 + y2 – 14x – 10y – 151 = 0