## Question

### Solution

Correct option is The co-ordinates of the centres and radii of three given circles are as given below:  and Let C ≡ (hk) be the centre of the circle passing through the centresC1(0, 2), C2(–6, –2) and C3(–3, –6).

Then          CC1 = CC2 = CC3     or                 3h + 2k + 9 = 0                      …(1)

and              6h – 8k – 5 = 0                       …(2)

solving (1) and (2), we get     Hence equation of required circle is #### SIMILAR QUESTIONS

Q1

Find the locus of the mid point of the chord of the circle x2 + y2 = a2which subtend a right angle at the point (pq).

Q2

Let a circle be given by

2x (x – a) + y(2y – b) = 0            (a ≠ 0, b ≠ 0)

Find the condition on a and b if two chords, each bisected by the x-axis, can be drawn to the circle from (ab/2).

Q3

The centre of the circle S = 0 lie on the line 2x – 2y + 9 = 0 and S = 0 cuts orthogonally the circle x2 + y2 = 4. Show that circle S = 0 passes through two fixed points and find their co-ordinates.

Q4 be a given circle. Find the locus of the foot of perpendicular drawn from origin upon any chord of Swhich subtends a right angle at the origin.

Q5 be a given circle. Find the locus of the foot of perpendicular drawn from origin upon any chord of Swhich subtends a right angle at the origin.

Q6

P is a variable on the line y = 4. Tangents are drawn to the circle x2 + y2= 4 from P to touch it at A and B. The perpendicular PAQB is completed. Find the equation of the locus of Q.

Q7

Find the condition on abc such that two chords of the circle

x2 + y2 – 2ax – 2by + a2 + b2 – c2 = 0

passing through the point (ab + c) are bisected by the line y = x.

Q8

Find the limiting points of the circles

(x2 + y2 + 2gx + c) + λ(x2 + y2 + 2fy + d) = 0

Q9

The circle x2 + y2 – 4x – 8y + 16 = 0 rolls up the tangent to it at by 2 units, assuming the x-axis as horizontal, find the equation of the circle in the new position.

Q10

Find the equation of the circle passing through (1, 0) and (0, 1) and having the smallest possible radius.