Find the local maximum and local minimum of f (x) = x3 + 3x in [–2, 4].
Minimum = –14 & Maximum = 76
Given, f (x) = x3 + 3x
which is strictly increasing for all x Ïµ R and thus, increasing for [–2, 4].
Hence, local minimum is f (–2) = (–2)3 + 3(–2) = –14
and local maximum is f (4) = (4)3 + 3(4) = 76.
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