A Particle Is Executing Simple Harmonic Motion. Its Displacement Is Given By                            Where x is In Cm And t in Seconds. How Long Will The Particle Take To Move From The Position Of Equilibrium To The Position Of Maximum Displacement?

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Question

 

A particle is executing simple harmonic motion. Its displacement is given by   

                       

where x is in cm and t in seconds. How long will the particle take to move from the position of equilibrium to the position of maximum displacement?

Solution

Correct option is

0.5 s

 

Maximum displacement = amplitude = 5 cm 

At time t = 0, x = 0 (equilibrium position). Hence time t taken by the particle to move from x = 0 to x = 5 cm is given by

                         

  

SIMILAR QUESTIONS

Q1

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Q2

A tray of mass M = 10 kg is supported on two identical springs, each of spring constant k, as shown in fig. When the tray is depressed a little and released, it executes simple harmonic motion of period 1.5 s. When a block of mass m is placed on the tray, the period of oscillation becomes 3.0 s. The value of m is  

                                                                 

Q3

A vertical U-tube of uniform cross-sectional area A contains a liquid of density ρ. The total length of the liquid column in the tube is L. The liquid column is disturbed by gently blowing into the tube. If viscous effects are neglected, the time period of the resulting oscillation of the liquid column is given by 

Q4

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Q5

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Q6

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Q7

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Q8

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Which of the following statements is/are true? 

Q9

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Q10

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