A big drop is formed by coalesing 1000 small droplets of water. What will be the change in surface energy?
What will be the ratio between the total surface energy of the droplets and the surface energy of the big drop?
10 : 1
Volume of big drop = volume of 1000 small droplets
R = 10 r
r = R/10
Let T be the surface tension of water. Then surface energy of 1000 droplets is
Surface energy of the big drop .
The surface energy will decrease
It will decrease to 1/10 of its previous value.
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[RD of metal = 14]
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