Question
A big drop is formed by coalesing 1000 small droplets of water. What will be the change in surface energy?
What will be the ratio between the total surface energy of the droplets and the surface energy of the big drop?
Solution
Correct option is
10 : 1
Volume of big drop = volume of 1000 small droplets
R = 10 r
r = R/10
Let T be the surface tension of water. Then surface energy of 1000 droplets is
.
Surface energy of the big drop .
The surface energy will decrease
.
It will decrease to 1/10 of its previous value.
SIMILAR QUESTIONS
Q1
A glass beaker having mass 390 g and an interior volume of 500 cm3 floats on water when it is less than half filled with water. What is the density of the material of the beaker?
Q2
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Q3
A wooden stick of length L, radius R and density has a small metal piece of mass m (of negligible volume) attached to its one end. Find the minimum value of the mass m (in terms of given parameters) that would make the stick float vertically in equilibrium in a liquid of density .
Q4
Calculate the rate of flow of glycerine of density through the conical section of a pipe, if the radii of its ends are 0.1 m and 0.04 m and the pressure drop across its length is 10 N/m2.
Q5
A non-viscous liquid of constant density 1000 kg/m3 flows in a streamline motion along a tube of variable cross-section. The tube is kept inclined in the vertical plane as shown in figure. The area of cross-section of the tube at two points P and Q at heights of 2 metre and 5 metre are respectively the velocity of the liquid at point P is 1 m/s. Find the work done per unit volume by the pressure and the gravity forces as the fluid flows from point P to Q.
Q6
The fresh water behind a reservoir dam is 15 m deep. A horizontal pipe 4.0 cm in diameter passes through the dam 6.0 m below the water surface as shown in figure. A plug secures the pipe opening. The plug is removed. What volume of water flows out of the pipe in 3.0- hour?
Q8
The surface tension of a soap solution is 0.03 N/m. How much work is required to form a bubble of 1.0 cm radius from this solution?
Q9
A mercury drop of radius 1.0 mm breaks up into 64 droplets of equal volumes. Calculate the work done in this process. (Surface tension is mercury is 0.465 N/m)
Q10
joule work is being done in breaking a big drop of water of radius R into 1000 small drops of equal size. Find out the surface tension of water.