Question

Solution

Correct option is

20 ms –1 at an angle of 30o with the horizontal

We know that the position coordinates x and y are given by  Comparing Eq. (i) with we have, Also, comparing Eq. (ii) with y = 10t – t2, we have, v0 sin θ = 10 ms–1. These equations give which gives θ = 30o.

SIMILAR QUESTIONS

Q1

It is possible to project a particle with a given velocity in two possible ways so as to make it pass through a point P at a distant r from the point of projection. The product of the times taken to reach this point in the two possible ways is then proportional to

Q2

At what angle (θ) with the horizontal should a body be projected so that its horizontal range equals the maximum height it attains?

Q3

A body is projected horizontally from a point above the ground. The motion of the body is described by the equations

x = 2t

and                    y = 5 t2

Where x and y are the horizontal and vertical displacements (in m) respectively at time t. The trajectory of the body is