Question

Solution

Correct option is Amplitude A = 60 microns = 60 × 10–6 m. Angular frequency ω = 1800 rad s–1 and wave number . Wave velocity is v = ω/k = 1800/6 = 300 ms–1. Maximum particle velocity Therefore, SIMILAR QUESTIONS

Q1

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Q2

A particle is executing simple harmonic motion along the x-axis with amplitude 4 cm and time period 1.2 s. The minimum time taken by the particle to move from x = +2 cm to x = +4 cm and back again is

Q3

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Q4

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Q5

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Q6

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Q7

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Q8

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Q9

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Q10

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