Question

Solution

Correct option is Shifting the origin at (3, –2), we have The equation of the ellipse with reference to new axes is Comparing it with , we get a2 = 36 and b2 = 16.

Let e be the eccentricity of this ellipse. Then,   The coordinates of the foci with reference to new axes are Substituting these in (i), we obtain the coordinates of foci as SIMILAR QUESTIONS

Q1

The eccentricity of the ellipse Q2

If the eccentricities of the two ellipse are equal, then the value , is

Q3

The curve represented by the equation , is

Q4

The equation of the ellipse whose axes are along the coordinate axes, vertices are (±5, 0) are foci at (±4, 0), is

Q5

The equation of the ellipse whose axes are along the coordinate axes, vertices are (0, ±10) and eccentricity e = 4/5, is

Q6

If the latusrectum of an ellipse is equal to one half of its minor axis, then the eccentricity is equal to

Q7

The eccentricity of the ellipse, if the distance between the foci is equal to the length of the latusrectum, is

Q8

The equation of the circle drawn with the two foci of as the end-points of  a diameter, is

Q9

The foci of the conic 25x2 +16y2 – 150x = 175 are

Q10

The vertices of the ellipse 