The foci of the ellipse are
Shifting the origin at (3, –2), we have
The equation of the ellipse with reference to new axes is
Comparing it with , we get a2 = 36 and b2 = 16.
Let e be the eccentricity of this ellipse. Then,
The coordinates of the foci with reference to new axes are .
Substituting these in (i), we obtain the coordinates of foci as .
The eccentricity of the ellipse
If the eccentricities of the two ellipse
are equal, then the value , is
The curve represented by the equation
The equation of the ellipse whose axes are along the coordinate axes, vertices are (±5, 0) are foci at (±4, 0), is
The equation of the ellipse whose axes are along the coordinate axes, vertices are (0, ±10) and eccentricity e = 4/5, is
If the latusrectum of an ellipse is equal to one half of its minor axis, then the eccentricity is equal to
The eccentricity of the ellipse, if the distance between the foci is equal to the length of the latusrectum, is
The equation of the circle drawn with the two foci of as the end-points of a diameter, is
The foci of the conic 25x2 +16y2 – 150x = 175 are
The vertices of the ellipse