## Question

### Solution

Correct option is

Shifting the origin at (3, –2), we have

The equation of the ellipse with reference to new axes is

Comparing it with , we get a2 = 36 and b2 = 16.

Let e be the eccentricity of this ellipse. Then,

The coordinates of the foci with reference to new axes are

Substituting these in (i), we obtain the coordinates of foci as

#### SIMILAR QUESTIONS

Q1

The eccentricity of the ellipse

Q2

If the eccentricities of the two ellipse

are equal, then the value , is

Q3

The curve represented by the equation

, is

Q4

The equation of the ellipse whose axes are along the coordinate axes, vertices are (±5, 0) are foci at (±4, 0), is

Q5

The equation of the ellipse whose axes are along the coordinate axes, vertices are (0, ±10) and eccentricity e = 4/5, is

Q6

If the latusrectum of an ellipse is equal to one half of its minor axis, then the eccentricity is equal to

Q7

The eccentricity of the ellipse, if the distance between the foci is equal to the length of the latusrectum, is

Q8

The equation of the circle drawn with the two foci of  as the end-points of  a diameter, is

Q9

The foci of the conic 25x2 +16y2 – 150x = 175 are

Q10

The vertices of the ellipse