Question

 

Find the equation of the hyperbola whose foci are (6, 4) and (–4, 4) and eccentricity is 2.

Solution

Correct option is

 

The centre of the hyperbola is the mid-point of the line joining the two foci. So the coordinates of the centre are  

          

Let 2a and 2b be the length of transverse and conjugate axes and let e be the eccentricity. Then equation of hyperbole is  

      

∴ Distance between the foci = 2ae

       

       

  

Thus the equation of the hyperbola is  

        

    

  

SIMILAR QUESTIONS

Q1

 

To find the equation of the hyperbola from the definition that hyperbola is the locus of a point which moves such that the difference of its distances from two fixed points is constant with the fixed point as foci.

 

Q2

Find the equation of the hyperbola whose directrix is 2x + y = 1, focus (1, 2) and eccentricity 

Q3

Find the eccentricity of the hyperbola whose latus rectum is half of its transverse axis.

Q4

Obtain the equation of a hyperbola with coordinate axes as principal axes given that the distances of one of its vertices from the foci are 9 and 1 units.

Q5

The foci of a hyperbola coincide with the foci of the ellipse . Find the equation of the hyperbola if its eccentricity is 2.

Q6

For what value of λ does the line y = 2x + λ touches the hyperbola  

Q7

Find the equation of the tangent to the hyperbola x2 – 4y2 = 36 which is perpendicular to the line x – y + 4 = 0.  

Q8

 

Find the equation and the length of the common tangents to hyperbola 

            

Q9

Find the locus of the foot of perpendicular from the centre upon any normal to the hyperbola .

Q10

Find the locus of the mid-points of the chords of the hyperbola  which subtend a right angle at the origin.