Let ABC be A Triangle With A(–1, –5), B(0, 0) And C(2, 2) And Let D be The Middle Point Of BC. Find The Equation Of The Perpendicular Drawn From Bto AD.

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Question

Let ABC be a triangle with A(–1, –5), B(0, 0) and C(2, 2) and let D be the middle point of BC. Find the equation of the perpendicular drawn from Bto AD.

diffcult

Solution

Correct option is

x + 3y = 0

âˆµ D is the middle point of BC.

i.e., D(1, 1)

Slope of the median AD

∴ Slope of BM which is perpendicular to AD = –1/3.

Hence equation of the line BM is

x + 3y = 0

which is the required equation of the line.

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