## Question

### Solution

Correct option is

The distance between the lines

5x – 12y + 2 = 0 and 5x – 12y – 3 = 0 is

I- Alternative Method: The constant term in both equations are 2 and –3 which are of opposite sign. Hence origin lies between them.

II- Alternative Method : Putting y = 0 in 5x – 12y – 3 = 0 then x = 3/5

Hence distance between the lines 5x – 12y + 2 = 0 and (5x – 12y – 3 = 0)

#### SIMILAR QUESTIONS

Q1

The centre of a square is at the origin and one vertex is A(2, 1). Find the coordinates of other vertices of the square.

Q2

The extremities of the diagonal of a square are (1, 1), (–2, –1). Obtain the other two vertices and the equation of the other diagonal.

Q3

Are the points (2, 1) and (–3, 5) on the same or opposite side of the line 3x – 2y + 1 = 0?

Q4

Is the point (2, –7) lie on origin side of the line 2x + + 2 = 0?

Q5

A straight canal is at a distance of  km from a city and the nearest path from the city to the canal is in the north-east direction. Find whether a village which is at 3 km north and 4 km east from the city lies on the canal or not. If not, then on which side of the canal is the village situated?

Q6

Find the general equation of the line which is parallel to

3x – 4y + 5 = 0. Also find such line through the point (–1, 2).

Q7

Find the general equation of the line which perpendicular to x + y + 4 = 0. Also find such line through the point (1, 2).

Q8

Find the sum of the abscissas of all the points on the line x + y = 4 that lie at a unit distance from the line 4x + 3y – 10 = 0.

Q9

If p and p’ are the length of the perpendiculars from the origin to the straight line whose equations are , then find the value of 4p2 + p2.

Q10

Find the equations of the line parallel to 5x – 12y + 26 = 0 and at a distance of 4 units from it.