## Question

### Solution

Correct option is

7x + 9y – 3 = 0, 9x – 7y – 41 = 0

Firstly make the constant terms (c1c2) positive, then

–4x – 3y + 6 = 0

and     5x + 12y + 9 = 0

∴ The equation of the bisector bisecting the angle containing origin is    or     7x + 9y – 3 = 0

and the equation of the bisector bisecting the angle no containing origin is    or    9x – 7y – 41 = 0.

#### SIMILAR QUESTIONS

Q1

The family of lines x(a + 2b) + y(+ 3b) = b passes through the point for all values of a and b. Find the point.

Q2

If 3a + 2b + 6c = 0 the family of straight lines ax + by + c = 0 passes through a fixed point. Find the coordinates of fixed point.

Q3

Find the equation of the line passing through the point of intersection of the lines

x + 5y + 7 = 0, 3x + 2y – 5 = 0 and

1. parallel to the line 7x + 2y – 5 = 0

2. perpendicular to the line 7x + 2y – 5 = 0

Q4

Find the equation of straight line which passes through the intersection of the straight lines

3x – 4y + 1 = 0 and 5x + y – 1 = 0

and cuts off equal intercepts from the axes.

Q5

Find the orthocentre of the triangle of the triangle ABC whose angular points are A(1, 2), B(2, 3) and C(4, 3).

Q6

If the orthocentre of the triangle formed by the lines

2x + 3y – 1 = 0, x + 2y – 1 = 0, ax + by – 1 = 0   is at origin, then find (a,b).

Q7

Find the equations of the straight lines passing through the point (2, 3) and inclined at π/4 radians to the line 2x + 3y = 5.

Q8

Find the equations to the straight lines passing through the point (2, 3) and equally inclined to the lines 3x – 4y – 7 = 0 and

12x – 5y + 6 = 0

Q9

Find the equation of the bisector of the obtuse angle between the lines 3x– 4y + 7 = 0 and 12x + 5y – 2 = 0.

Q10

Find the bisector of acute angle between the lines x + y – 3 = 0 and 7x – y+ 5 = 0.