The chance of an event happening is the square of the chance of happening of second event but the odds against the first are the cube of the odds against the second. The chance of the events:
None of these
Let the first event be A and second event be B. according to question we can assume,
it is given in the question that odd against A is cube of odd against B.
⇒ Either x = 1
Three integers are chosen at random without replacement from the first 20 integers. The probability that their product is even 2/19.
A box contains tickets numbered 1 to N. n tickets are drawn from the box with replacement. The probability that the largest number on the tickets is k is
A box contain N coins, m of which are fair and rest are biased. The probability of getting a head when a fair coin is tossed is 1/2, when a baised coin is tossed. A coin is drawn from the box at random and is tossed twice. The first time it shows head and the second time it shows tail. The probability that the coin drawn is fair is
Given that A, B and C are events such that P(A) = P(B) = P(C) = 1/5, P(A∩ B) = P(B ∩ C) = 0 and P(A ∩ C) = 1=10. The probability that at least one of the events A, B or C occurs is …….
Let A and B be two events such that
A and B toss a coin alternatively till one of them gets a head and wins the game. If A begins the game, the probability B wins the game is
Suppose X ~ B(n, p) and P(X = 5). If p > 1/2, then
A person is known to speak the truth 4 time out of 5. He throws a dia and reports that it is a ace. The probability that it is actually a ace is
In a game called “odd man out man out”, m(m > 2) persons toss a coin to determine who will buy refreshments for the entire group. A person who gets an outcome different from that of the rest of the members of the group is called the odd man out. The probability that there is a loser in any game is
The odd against a certain event are 5: 2 and the odds in favour of another independent event are 6: 5 the probability that at least one of the events will happen is: