## Question

### Solution

Correct option is

Rhombus

The equations of the straight lines represented by the two equations are  Clearly, we have two sets of parallel straight lines. So, they form a parallelogram. Also, the distance between (i) and (ii) is same as the distance between (iii) and (iv) each equal to 2|a|. So, the given lines form a rhombus.

#### SIMILAR QUESTIONS

Q1

If two pairs of straight lines having equations have one line common then a =

Q2

The point of intersection of the The Pair of Straight Lines given by Q3

The square of the distance between the origin and the point of intersection of the lines given by Q4

The centroid of the triangle whose three sides are given by the combined equation Q5

If first degree terms and constant term are to be removed from the equation , then the origin must be shifted at the point

Q6

The angle between the straight lines joining the origin to the points of intersection of and 3x – 2y = 1 is

Q7

All chords of the curve which subtend a right angle at the origin always pass through the point

Q8

If the pair of lines represented by intersect on y-axis, then

Q9

If the chord y = mx + 1 of the circle x2 + y2 = 1 subtends an angle of 45oat the major segment of the circle, then m =

Q10

The equation  of the image of the pair of rays in the line mirror x= 1 is