﻿    In the reaction,       2 Al(s) + 6 HCl (aq) → 2 Al3+(aq) + 6 Cl– (aq) + 3 H2 (g) : Kaysons Education

# In The Reaction,       2 Al(s) + 6 HCl (aq) → 2 Al3+(aq) + 6 Cl– (aq) + 3 H2 (g)

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## Question

### Solution

Correct option is

11.2 L H2 (g) at STP is produced for every moleHCl (aq) consumed

2 Al (s) + 6 HCl (aq) → 2 Al3+ (aq) + 6 Cl (aq) + 3 H2 (g)

Thus 6 moles of HCl produced H2 at STP

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