In the reactions
two isomers of the product are obtained. The initial complex is
The initial complex must have two Cl– ions in cis position as the third Cl–ion could replace an ammonia cis to both or trans to one giving two isomers. If two Cl– ions were in the trans positions, the other four oppositions which could be replaced are equivalent and only one isomer of the product would be obtained.
Octahedral complex of Ni (II) must be
Octahedral complex of Cr(III) will be
For the correct assignment of electronic configuration of a complex, the valence bond theory often requires the measurement of
Mn2+ forms a complex with Br– ion. The magnetic moment of the complex is 5.92 B.M. What would be the probable formula and geometry of the complex?
How many isomers are possible for the complex ion [Cr(NH3)(OH)2Cl3]2–
A complex of certain metal has the magnetic moment of 4.91 BM whereas another complex of the same metal with same oxidation state has zero magnetic moment. The metal ion could be
The EAN of metal atoms in Fe(NO)2(CO)2 and Co2(CO)8 respectively are
The value of x in HxCr(CO)5 is
Following Sidwick’s rule of EAN, Co2(CO)x will be
On treatment of [Ni(NH3)4]2+ with concentrated HCl, two compounds I and II having the same formula, Ni(NH3)2Cl2 are obtained. I can be converted into II by boiling with dilute HCl. A solution of I reacts with oxalic acid to form [Ni(NH3)2(C2O4) whereas II does not react. Point out the correct statement of the following