Three different solutions were prepared by dissolving same amounts of the following complexes I, II, III in water. The freezing points of these solutions were then determined. The correct orders of freezing points will be :
II. [Co(NH3)5(NO2)]2+ [Co(NH3)2(NO2)4]2
[Given : Kf(H2O) = 1.86oC/m]
I = II = III
In each case same number of mole particles are formed so is same.
Which is not a π-acceptor ligand?
A complex of a certain metal ion has a magnetic moment of 4.90 B.M. Another complex of the same metal ion in the same oxidation state has a zero magnetic moment. Which of the following could be the central metal ion in the two complexes?
Which of the following is most acidic aqua ion?
Select the complex in which secondary valency is satisfied before the primary valency.
We get a copper complex with ammonia having the formula [Cu(NH3)4]2+only in alkaline solution and not in acidic solution. It can be explained on the basis of the fact that :
The molecular formula of both ‘A’ and ‘B’ is same.
‘A’ can be converted to B be boiling in dil. HCl.
‘A’ on reaction with oxalic acid yields a complex having the formula Ni(NH3)2(C2O4) but ‘B’ does not.
From the above information we can say that
Select the complex that can be reduced most easily.
0.001 mol of cobalt complex having molecular formula represented by Co(NH3)5(NO3)(SO4) was passed through a cation exchange (RSO3H) and the acid coming out of it was titrated with 0.1 M NaOH solution. For complete neutralization of acid coming out of cation exchanger the volume of NaOH required was 20.00 ml. From the above data we can say that the complex can be represented as
The correct order of ligands in the trans-directing series is
Effective atomic number (EAN) of Fe in brown ring complex [Fe(H2O)5NO]2+