## Question

### Solution

Correct option is

1.212 V

Since the Eo of Fe2+/Fe(– 0.441 V) is lower than that of Fe3+/Fe2+ (+ 0.771 V) electrode, therefore, oxidation occurs at Fe2+/Fe electrode and reduction at Fe3+/Fe2+ electrode. = 0.771 V – (– 0.441 V) = 1.212 V.

#### SIMILAR QUESTIONS

Q1

The values of x and y in the following redox reaction, Q2

In the standardization of Na2S2O3 using K2Cr2O7 by iodometry, the equivalent weight of K2Cr2O7 is

Q3

When KMnO4 acts as an oxidising agent and ultimately forms , then the number of electrons transferred in each case respectively is

Q4

For decolourization of 1 mole of KMnO4, the moles of H2O2 required is

Q5

Excess of KI reacts with CuSO4 solution and Na2S2O3 solution is added to it. Which of the statements is incorrect foe the reaction?

Q6 The above equation balances when

Q7

The number of moles of KMnO4 reduced by one mole of KI in alkaline medium is

Q8

Which of the following will not be oxidised by O3?

Q9

A hypothetical electrochemical cell is shown below The emf measured is + 0.20 V. The cell reaction is

Q10

Which of the following chemical reactions depicts the oxidising behavior of H2SO4?