﻿   The locus rectum of the hyperbola 9x2 – 16y2 – 18x – 32y – 151 = 0 is : Kaysons Education

# The Locus Rectum Of The Hyperbola 9x2 – 16y2 – 18x – 32y – 151 = 0 Is

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## Question

### Solution

Correct option is

9x2 – 16y2 – 18x – 32y – 151 = 0

⇒  9(x – 1)2 – 16(y – 1)2 = 144

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