, for every real number, then minimum value of f
The coordinates of the point on the parabola y2 = 8x which is at minimum distance from the circle x2 + (y + 6)2 = 1 are
The image of the interval [- 1, 3] under the maping
f (x) = 4x2 – 12x is.
The difference between the greatest and least values of the function