Question

Solution

Correct option is Slope of the normal to the rectangular hyperbola xy = 4 is m = t2 = 2 and 2x – y = 5 has slope = 2. Equation of the normal is  ⇒      ty – 2 = 2tx – 4t2

⇒    2tx – ty + 2 – 4t2  SIMILAR QUESTIONS

Q1

Sa circle with fixed center (3h, 3k) and of variable radius cuts the rectangular hyperbola x2 – y2 = 9a2 at the points A, B, C, D. The locus of the centroid of the triangle ABC is given by

Q2

If PQ is a double ordinate of the hyperbola such the OPQ is an equilateral triangle, O being the centre of the hyperbola. Then the eccentricity e of the hyperbola satisfies –

Q3

A rectangular hyperbola passes through the points A(1, 1), B(1, 5) and C(3, 1). The equation of normal to the hyperbola at A(1, 1) is –

Q4

If a variable line which is a chord of the hyperbola subtends a right angle at the centre of the hyperbola then it always touches a fixed circle whose radius is –

Q5

If values of m for which the line touches the hyperbola 16x2 – 9y= 144 are the roots of the equation x2 –(a + b)x – 4 = 0, then value of (a + b) is equal to –

Q6

A tangent to the hyperbola meets ellipse x2 + 4y2 = 4 in two distinct points. Then the locus of midpoint of this chord is –

Q7

From a point on the line y = x + c, c(parameter), tangents are drawn to the hyperbola such that chords of contact pass through a fixed point (x1, y1). Then is equal to –

Q8

If the portion of the asymptotes between centre and the tangent at the vertex of hyperbola in the third quadrant is cut by the line being parameter, then –

Q9

Find the eccentricity of the hyperbola whose latus rectum is half of its transverse axis.

Q10

For what value of c does not line y = 2x + c touches the hyperbola 16x2 – 9y2 = 144?