## Question

### Solution

Correct option is

20

Equation of hyperbola is

16x2 – 9y2 = 144 Comparing this with , we get a2 = 9, b2 = 16.

And comparing this line y = 2x + c with y = mx + c. ⇒m = 2, c = 1

If the line y = 2x + 1 touches the hyperbola

16x2 – 9y2 = 144    then    c2 = a2m2 – b2

⇒ c2 = 9(2)2 – 16 = 36 – 16 = 20 #### SIMILAR QUESTIONS

Q1

If values of m for which the line touches the hyperbola 16x2 – 9y= 144 are the roots of the equation x2 –(a + b)x – 4 = 0, then value of (a + b) is equal to –

Q2

The equation of normal to the rectangular hyperbola xy = 4 at the point P on the hyperbola which is parallel to the line

2x – y = 5 is –

Q3

A tangent to the hyperbola meets ellipse x2 + 4y2 = 4 in two distinct points. Then the locus of midpoint of this chord is –

Q4

From a point on the line y = x + c, c(parameter), tangents are drawn to the hyperbola such that chords of contact pass through a fixed point (x1, y1). Then is equal to –

Q5

If the portion of the asymptotes between centre and the tangent at the vertex of hyperbola in the third quadrant is cut by the line being parameter, then –

Q6

Find the eccentricity of the hyperbola whose latus rectum is half of its transverse axis.

Q7

Determiner the equation of common tangents to the hyperbola and .

Q8

Find the locus of the mid-pints of the chords of the circle x2 – y2 = 16, which are tangent to the hyperbola 9x2 – 16y2 = 144.

Q9

Find the locus of the poles of the normal of the hyperbola .

Q10

Obtain the equation of a hyperbola with coordinate axes as principal axes given that the distance of one of its vertices from the foci are 9 and 1 units.