The Equation Of Common Tangent To The Curves y2 = 8x and xy = –1 Is

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Question

The equation of common tangent to the curves y2 = 8x and xy = –1 is

Solution

Correct option is

y = x + 2

y2 = 8x = 4ax

                 … (3)

(3) is also tangent for curve (2), Now (2) and (3)

   

For common tangent this eq. will have one root.

     B2 – 4AC = 0

    

So put this to get y = x + 2

SIMILAR QUESTIONS

Q1

The pints of intersection of the two ellipse x2 + 2y2 – 6x – 12y + 23 = 0 and 4x2 + 2y2 – 20x – 12y + 35 = 0.

Q2

The tangent at any point P of the hyperbola  makes an intercept of length p between the point of contact and the transverse axis of the hyperbola, p1p2 are the lengths of the perpendiculars drawn from the foci on the normal at P, then

Q3

The length of chord of contact of the tangents drawn from the point (2, 5) to the parabola y2 = 8x, is 

Q4

The locus of a point whose some of the distance from the origin and the line x = 2 is 4 units, is

Q5

The length of the subnormal to the parabola y2 = 4ax at any point is equal to

Q6

The slope of the normal at the point (at2, 2at) of parabola y2 = 4ax  is

Q7

Equation of locus of a point whose distance from point (a, 0) is equal to its distance from y-axis is

Q8

Through the vertex O of parabola y2 = 4x, chords OP and OQ are drawn at right angles to one another. The locus of the middle point of PQ is

Q9

The locus of the mid-point of the line segment joining the focus to a moving point on the parabola y2 = 4ax is another parabola with directrix

Q10

From the point (–1, 2) tangent lines are drawn to the parabola y2 = 4x, then the equation of chord of contact is