The equation of tangent at the point (1, 2) to the parabola y2 = 4ax, is
x – y + 1 = 0
y2 = 4ax
Equation of tangent at P is
x – y + 1 = 0.
For the above problem, the area of triangle formed by chord of contact and the tangents is given by
A point moves on the parabola y2 = 4ax. Its distance from the focus is minimum for the following value(s) of x.
The line x – y + 2 = 0 touches the parabola y2 = 8x at the point
If t is the parameter for one end of a focal chord of the parabola y2 = 4ax, then its length is
The point on the parabola y2 = 8x at which the normal is inclined at 600 to the x-axis has the coordinates
The length of the latus rectum of the parabola 9x2 – 6x + 36y + 19 = 0 is
The equation of a circle passing through the vertex the extremities of the latus rectum of the parabola y2 = 8x is
If the parabola y2 = 4ax passes through the pint (1, –2), then the tangent at this point is
The equation of normal at the point to the parabola y2 = 4ax, is
If a tangent of y2 = ax made angle of 450 with the x-axis, then its point of contact will be