﻿ The equation of tangent at the point (1, 2) to the parabola y2 = 4ax, is : Kaysons Education

# The Equation Of Tangent At The Point (1, 2) To The Parabola y2 = 4ax, Is

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## Question

### Solution

Correct option is

x – y + 1 = 0

y2 = 4ax

Equation of tangent at P is

.

x – y + 1 = 0.

#### SIMILAR QUESTIONS

Q1

For the above problem, the area of triangle formed by chord of contact and the tangents is given by

Q2

A point moves on the parabola y2 = 4ax. Its distance from the focus is minimum for the following value(s) of x.

Q3

The line x – y + 2 = 0 touches the parabola y2 = 8x at the point

Q4

If t is the parameter for one end of a focal chord of the parabola y2 = 4ax, then its length is

Q5

The point on the parabola y2 = 8x at which the normal is inclined at 600 to the x-axis has the coordinates

Q6

The length of the latus rectum of the parabola 9x2 – 6x + 36y + 19 = 0 is

Q7

The equation of a circle passing through the vertex the extremities of the latus rectum of the parabola y2 = 8x  is

Q8

If the parabola y2 = 4ax passes through the pint (1, –2), then the tangent at this point is

Q9

The equation of normal at the point  to the parabola y2 = 4ax, is

Q10

If a tangent of y2 = ax made angle of 450 with the x-axis, then its point of contact will be