The Equation Of Tangent At The Point (1, 2) To The Parabola y2 = 4ax, Is

For the above problem, the area of triangle formed by chord of contact and the tangents is given by

A point moves on the parabola y² = 4ax. Its distance from the focus is minimum for the following value(s) of x.

The line x – y + 2 = 0 touches the parabola y² = 8x at the point

If t is the parameter for one end of a focal chord of the parabola y² = 4ax, then its length is

The point on the parabola y² = 8x at which the normal is inclined at 60⁰ to the x-axis has the coordinates

The length of the latus rectum of the parabola 9x² – 6x + 36y + 19 = 0 is

The equation of a circle passing through the vertex the extremities of the latus rectum of the parabola y² = 8x  is

If the parabola y² = 4ax passes through the pint (1, –2), then the tangent at this point is

The equation of normal at the point  to the parabola y² = 4ax, is

If a tangent of y² = ax made angle of 45⁰ with the x-axis, then its point of contact will be