﻿ The straight line y = mx + c touches the parabola y2 = 4a(x + a) if : Kaysons Education

# The Straight Line y = Mx + C touches The Parabola y2 = 4a(x + A) If

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## Question

### Solution

Correct option is

y2 = 4a(x + a)     … (1)

put x + a = X, then y2 = 4ax its tangent is

. Compare with y = mx + c

#### SIMILAR QUESTIONS

Q1

The equation of tangent at the point (1, 2) to the parabola y2 = 4ax, is

Q2

If a tangent of y2 = ax made angle of 450 with the x-axis, then its point of contact will be

Q3

If a normal drawn to the parabola y2 = 4ax at the point (a, 2a) meets parabola again on (at2, 2at), then the value of t will be

Q4

If the straight line x + y = 1 touches the parabola y2 – y + x = 0, then the coordinates of the point of contact are

Q5

The angle of intersection between the curves y2 = 4x and x2 = 32y at point (16, 8) is

Q6

The pole of the line lx + mx + n = 0 with respect to the parabola y2 = 4ax is

Q7

Two tangent are drawn from the point (–2, –1) to the parabola y2 = 4x. if  is the angle between them, then

Q8

The conic represented by the equation  is

Q9

If (4, 0) is the vertex and y-axis, the directrix of a parabola then its focus is

Q10

The focus of the parabola x2 – 2x – y + 2 = 0 is