## Question

### Solution

Correct option is

(0, 0)(4, 12)

y2 = 36x          … (1)

(x, y) is a point on (1) such that y = 3x

Now (1) (3x)2 = 36x x = 0, 4 y = 0, 12 (0, 0)(4, 12).

#### SIMILAR QUESTIONS

Q1

The straight line y = mx + c touches the parabola y2 = 4a(x + a) if

Q2

The focus of the parabola x2 – 2x – y + 2 = 0 is

Q3

If P1Q1 and P2Q2 are two focal chords of the parabola y2 = 4ax, then the chords P1P2 and Q1Q2 intersect on the

Q4

The condition that the line be a normal to the parabola

y2 = 4ax is

Q5

The equation of the normal to the hyperbola y2 = 4x, which passes through the point (3, 0), is

Q6

PQ is a double of the parabola y2 = 4ax. The locus of the points of trisection of PQ is

Q7

The locus of the point of intersection of the lines bxt – ayt = ab and bx + ay = abt is

Q8

The line will touch the parabola y2 = 4a(x + a), if

Q9

The equation of the parabola whose axis is vertical and passes through the points (0, 0), (3, 0) and (–1, 4), is

Q10

The points on the parabola y2 = 12x whose focal distance is 4, are