﻿ Show that the normal at a point (at2, 2at) on the parabola y2 = 2ax cuts the curve again at the point whose parameter . : Kaysons Education

Show That The Normal At A Point (at2, 2at) On The Parabola y2 = 2ax cuts The Curve Again At The Point Whose Parameter .

Video lectures

Access over 500+ hours of video lectures 24*7, covering complete syllabus for JEE preparation.

Online Support

Practice over 30000+ questions starting from basic level to JEE advance level.

National Mock Tests

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

Organized Learning

Proper planning to complete syllabus is the key to get a decent rank in JEE.

Test Series/Daily assignments

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

Question

Solution

Correct option is

SIMILAR QUESTIONS

Q1

x – 2 = t2y = 2t are the parameter equations of the parabola

Q2

The equation  represents a parabola if  is

Q3

t1’ and ‘t2’ are two points on the parabola y2 = 4x. If the chord joining them is a normal to the parabola at ‘t1’ then

Q4

The vertex of the parabola y2 = 8x is at the center of a circle and the parabola cuts the circle at the ends of its latus rectum. Then the equation of the circle is

Q5

Find the equation of the parabola whose focus is (1, 1) and the directrix is x + y + 1 = 0.

Q6

If the line 2x + 3y = 1 touch the parabola y2 = 4ax at the pointP. Find the focal distance of the point P.

Q7

Find the angle between the tangents of the parabola y2 = 8x, which are drawn from the point (2, 5).

Q8

Find the locus of middle point of chord y2 = 4ax drawn through vertex.

Q9

Find the locus of the mid-point of the chords of the parabola y2 = 4ax which subtend a right angle at the vertex of the parabola.

Q10

Show that the normal at a point (at2, 2at) on the parabola y2 = 2ax cuts the curve again at the point whose parameter .