﻿ The point of intersection of the perpendicular tangents to the ellipse  lies on a circle square of whose radius is   : Kaysons Education

# The Point Of Intersection Of The Perpendicular Tangents To The Ellipse  lies On A Circle Square Of Whose Radius Is

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## Question

### Solution

Correct option is

2906

Any tangent to the ellipse is

and perpendicular to it is

Eliminating m we get the locus of the point of intersection of these tangents.

(y – mx)2 + (mx + x)2 = (1 + m2)[(41)2 + (35)2]

x2 + y2 = (41)2 + (35)2 which is a circle square of whose radius = (41)2 + (35)2 = 1681 + 1225 = 2906.

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