If x + Y = K is A Normal To The Parabola y2 = 12x, p is The Length Of The Perpendicular From The Focus Of The Parabola On This Normal; Then 3k2 + 2p2 is Equal To

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If x + y = k is a normal to the parabola y2 = 12xp is the length of the perpendicular from the focus of the parabola on this normal; then 3k2 + 2p2 is equal to


Correct option is


For the parabola y2 = 12x, equation of a normal will slope –1, is

              y = – x – 2(3)( –1) – (3)( –1)3           [m = –1, a = 3]

     x + y = 9  so  k = 9

Focus of the parabola is (3, 0)

    3k2 + 2p2 = 2223.



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