Question
If the length of the semi major axis of an ellipse is 68 and the eccentricity is then the area of the rectangle formed by joining the vertices of the latera of the ellipse is equal to

5426

6846

6936

None of these
easy
Solution
6936
Let the equation of the ellipse be where a^{2} = (68)^{2}and b^{2} = (68)^{2} vertices of the lateral recta are
Area of the rectangle formed by joining these points
= 6936.
SIMILAR QUESTIONS
If L is the chord of contact of the hyperbola H, then the equation of the corresponding pair of tangents is
If R is the point of intersection of the tangents to H at the extremities of the chord L, then equation of the chord contact of R with respect to the parabola P is
If the chord of contact of R with respect to the parabola Pmeets the parabola at T and T’, S is the focus of the parabola, then Area of the triangle STT’ is equal to
Tangent are drawn from any point on the hyperbola to the circle x^{2} + y^{2} = 9. If the locus of the midpoint of the chord of contact is
If l is the length of the intercept made by a common tangent to the circle x^{2} + y^{2 }= 16 and the ellipse , on the coordinate axes, then 81l^{2}+ 3 is equal to
If d is the length of the tangent from the point (100, 81) to the ellipse , then d2 is equal to
The point of intersection of the perpendicular tangents to the ellipse lies on a circle square of whose radius is
If x + y = k is a normal to the parabola y^{2} = 12x, p is the length of the perpendicular from the focus of the parabola on this normal; then 3k^{2} + 2p^{2} is equal to
If CF is perpendicular from the center C of the ellipse on the tangent at any point P, and G is the point where the normal at P meets the minor axis, then (CF. PG)^{2} is equal to
If e_{1} is the eccentricity of the ellipse and e_{2 }is the eccentricity of the hyperbola and e_{1}e_{2} = 1, then b^{2} is equal to