﻿ Show that 11n+2 + 122n+1 is divisible by 133. : Kaysons Education

# Show That 11n+2 + 122n+1 is Divisible By 133.

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## Question

### Solution

Correct option is

133

11n+2 + 122n+1 = 112. 11n + 12(144)n

Now 144 and 121 should be expression in terms of 133; 144 as (133 + 11) or 121 as (133 – 12)

= 121. 11n + 12(11 + 133)n

= 11n. 133 + terms containing 133 as a factor

Hence the expression is divisiable by 133.

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