The Number Of Terms In (1 + x)101 (1 + x2 – x)100 is

Why Kaysons ?

Video lectures

Access over 500+ hours of video lectures 24*7, covering complete syllabus for JEE preparation.

Online Support

Practice over 30000+ questions starting from basic level to JEE advance level.

Live Doubt Clearing Session

Ask your doubts live everyday Join our live doubt clearing session conducted by our experts.

National Mock Tests

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

Organized Learning

Proper planning to complete syllabus is the key to get a decent rank in JEE.

Test Series/Daily assignments

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

SPEAK TO COUNSELLOR ? CLICK HERE

Question

The number of terms in (1 + x)101 (1 + x2 – x)100 is

Solution

Correct option is

202

E = (1 + x)1 [(1 + x) (1 + x2 – x)]100­

   = (1 + x) (1 +x3)100

   = (1 + x) [101 terms in (1 + x3)100]

   = 101 + 101 = 202 terms in E.

SIMILAR QUESTIONS

Q1

If the sum of the coefficients in the expression of (1 + 2x)n is 6561. The greatest term in the expression at x = 1/2 is

Q2

The number of terms in the expression of (a + b + c)n, where n Ïµ N, is

Q3

The number of terms which are free from fractional powers in the expansion of (a1/5 + b2/3)45a ≠ b is

Q4

If n is an odd natural, then  equals

Q5
Q6

The coefficient of xm in (1 + x)r + (1 + x)r+1 + (1 + x)r+2 +….+ (1 + x)nr≤ m ≤ n is

Q7

 respect to x, is

Q8

 is a polynomial of degree 5, then n

Q9

If in the expression of (1 + x)m (1 – x)n. the coefficient of x and x2 are 3 and – 6 respectively, then m is

Q10

In the binomial expansion of (a – b)n, n ≤ 5, the sum of the 5th and 5thterms is zero. Then  equals