﻿ The number of terms in (1 + x)101 (1 + x2 – x)100 is : Kaysons Education

# The Number Of Terms In (1 + x)101 (1 + x2 – x)100 is

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## Question

### Solution

Correct option is

202

E = (1 + x)1 [(1 + x) (1 + x2 – x)]100­

= (1 + x) (1 +x3)100

= (1 + x) [101 terms in (1 + x3)100]

= 101 + 101 = 202 terms in E.

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