Let A0, A1 A2 A3 A4 A5 be a regular hexagon described in a circle of unit radius. Then the product of the length of the line segments A0 A1, A0 A2and A0 A4 is
Let OA0 = 1
then OA1 = OA2 = OA3 = OA4 = OA5 = 1 and A0(1, 0), A3(–1, 0)
Since each side of the hexagon makes an angle of 60o at the centre O of the circle coordinates of A1, A2, A4, A5, are respectively (cos 60o, sin 60o), (cos 120o, sin 120o),
(–cos 60o, – sin 60o)
If a, b, c form a G.P. with common ratio r, the sum of the ordinates of the points of intersection of the line ax + by + c = 0 and the curve x + 2y2= 0 is
Orthocenter of the triangle with vertices (0,0), (3, 4) and (4, 0) is
The number of integral points (integral point means both the coordinates should be integer) that lie exactly in the interior of the triangle with vertices (0, 0), (0, 21), and (21, 0) is
Let P = (–1, 0), Q = (0, 0) and R = be three points. Then the equation of the bisector of the angle PQR is
A straight line through the origin O meets the parallel lines 4x + 2y = 9 and 2x + y + 6 = 0 at points P and Q respectively. Then the point O divides the segment PQ in the ratio.
The diagonals of a parallelogram PQRS are long the lines
x + 3y = 4 and 6x – 2y = 7, then PQRS must be a
The orthocenter of the triangle formed by the lines xy = 0 and x + y = 1 is
The straight lines x + y = 0, 3x + y – 4 = 0, x + 3y – 4 = 0 form a triangle which is
If sum of the distances of a point from two perpendicular lines in a plane is 1, then its locus is
If the circumcentre of a triangle lies at the origin and centroid is the middle point of the line joining the points (a2 + 1, a2 + 1) and (2a, –2a), then the orthocenter lies on the line.