## Question

### Solution

Correct option is

(a –1)2 x – (a + 1)2 y = 0

We know from geometry that the circumcentre, centroid and orthocentre of a triangle lie on a line. So the orthocentre of the triangle lies on the line joining the circumcentre (0, 0) and the centroid   #### SIMILAR QUESTIONS

Q1

Orthocenter of the triangle with vertices (0,0), (3, 4) and (4, 0) is

Q2

The number of integral points (integral point means both the coordinates should be integer) that lie exactly in the interior of the triangle with vertices (0, 0), (0, 21), and (21, 0) is

Q3

Let P = (–1, 0), Q = (0, 0) and be three points. Then the equation of the bisector of the angle PQR is

Q4

A straight line through the origin O meets the parallel lines 4x + 2y = 9 and 2x + y + 6 = 0 at points P and Q respectively. Then the point O divides the segment PQ in the ratio.

Q5

Let A0A1 2 A3 A4 A5 be a regular hexagon described in a circle of unit radius. Then the product of the length of the line segments A A1A0 A2and A0 A4 is

Q6

The diagonals of a parallelogram PQRS are long the lines

x + 3y = 4 and 6x – 2y = 7, then PQRS must be a

Q7

The orthocenter of the triangle formed by the lines xy = 0 and x + y = 1 is

Q8

The straight lines x + y = 0, 3x + y – 4 = 0, x + 3y – 4 = 0 form a triangle which is

Q9

If sum of the distances of a point from two perpendicular lines in a plane is 1, then its locus is

Q10

If abc are unequal and different from 1 such that the points are collinear, then