If a, b, c are Unequal And Different From 1 Such That The Points  are Collinear, Then  

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If abc are unequal and different from 1 such that the points  are collinear, then  


Correct option is

bc + ca + ab – abc = 3 (a + b + c)

Suppose the given points lie on the line

lx + my + n = 0

then a, b, c are the roots of the equation.  


⇒                    a + b + c = –m/l  

                       bc + ca + ab = n/l  

                       abc = (3m + n)/  

Eliminating lmn, we get

              abc = –3(a + b + c) + bc + ca + ab  

⇒          bc + ca + ab – abc = 3(a + b + c)



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