Question

Find the distance between the lines 5x + 12y + 40 = 0 and 10x + 24y – 25 = 0.

 

Solution

Correct option is

Here, coefficients of x and y are not the same in both the equations. So, we write them as 

                   5x + 12y + 40 = 0

                   5x + 12y – 25/2 = 0   

SIMILAR QUESTIONS

Q1

Find the equation of the straight line upon which the length of perpendicular from origin is  units and this perpendicular makes an angle of 75o with the positive direction of x-axis.

Q2

Find the value of k so that the straight line 2x + 3y + 4 + k (6x – y + 12) = 0 and 7x + 5y – 4 = 0 are perpendicular to each other.

Q3

Show that the lines 2x – y – 12 = 0 and 3x + y – 8 = 0 intersect at a points which is equidistant from both the coordinates areas.

Q4

Find the area of triangle formed by the lines x – y + 1 = 0, 2x + y + 4 = 0 and x + 3 = 0.  

Q5

The line x + λy – 4 = 0 passes through the point of intersection of 4x – y+ 1 = 0 and x + y + 1 = 0. Find the values of λ.

Q6

Find the equation of a line parallel to x + 2y = 3 and passing through the point (3, 4).

Q7

Find the equation of the line perpendicular to 2x – 3y = 5 and cutting off an intercept 1 on the x-axis

Q8

Find the equation of the straight line passing through (2, –9) and the point of intersection of lines 2x + 5y – 8 = 0,

3x – 4y – 35 = 0  

Q9

Find the equation of straight line passing through the point of intersection of lines 3x – 4y +1 = 0, 5x + y – 1 = 0 and cutting off equal intercepts from coordinate axes.

Q10

If P is (1, 2) and the line mirror is 2x – y + 4 = 0, find the coordinates of its image (i.e., Q).