A straight line passes through (2, 3) and the portion of the line intercepted between the axes is bisected at this point. Find its equation
3x + 2y – 12 = 0
Let the required equation of the line be:
The above line meets the X–axis and Y–axis in points (a, 0) and (0, b) respectively
Now the point which bisects the join o f (a, 0) and (b, 0) has coordinates:
But its given as ≡ (2, 3)
So on comparing, we get a = 4, b = 6
Substituting the values of a and b in (i), we get:
or 3x + 2y – 12 = 0 is the required equation.
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