Question

Given the triangle with vertices A (–4, 9), B (10, 4), C (–2, –1). Find the equation of the altitude through A.

Solution

Correct option is

12x + 5y + 3 = 0

We have m1m2 = –1 for two perpendicular lines  

                                                     

⇒ Equation of line through A (–4, 9) and having slope = –12/5 is given by:

                         y – 9 = –12/5 (x + 4)

[using: y – y1 = m(x – x1)] 

or                    12x + 5y + 3 = 0 is the required equation. 

SIMILAR QUESTIONS

Q1

If the pair of lines x2 – 2pxy – y2 = 0 and x2 – 2qxy – y2 = 0 are such that each pair bisects the angle between the other pair, then pq equals  

Q2

Angles made with x-axis by the two lines through the point  (1, 2) and cutting the line x + y = 4 at a distance  from the point (1, 2) are

Q3

If the algebraic sum of the perpendicular distances of a variable line from the points (0, 2), (2, 0) and (1, 1) is zero, then the line always passes through the point

Q4

 be three points. Then the equation of the bisector of angle PQR is

Q5

Find the area of triangle ABC with vertices A (aa2), B (bb2), C (cc2).

Q6

A straight line passes through (2, 3) and the portion of the line intercepted between the axes is bisected at this point. Find its equation

Q7

Find the slope (m), intercepts on X axis, intercept on Y axis of the line 3x+ 2y – 12 = 0. Also trace the line on XY plane.

Q8

Given the triangle A (10, 4), B(–4, 9), C(–2, 1), find the equation of median through B.

Q9

Find the equation of the straight line passing through the points (3, 3) and (7, 6). What is the length of the portion of the line intercepted between the axes of the coordinates.

Q10

Find the equation of perpendicular bisector of the line joining the points (1, 1) and (2, 3).