Given The Triangle With Vertices A (–4, 9), B (10, 4), C (–2, –1). Find The Equation Of The Altitude Through A.

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Question

Given the triangle with vertices A (–4, 9), B (10, 4), C (–2, –1). Find the equation of the altitude through A.

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Solution

Correct option is

12x + 5y + 3 = 0

We have m₁m₂ = –1 for two perpendicular lines

⇒ Equation of line through A (–4, 9) and having slope = –12/5 is given by:

y – 9 = –12/5 (x + 4)

[using: y – y₁ = m(x – x₁)]

or 12x + 5y + 3 = 0 is the required equation.

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