Question

Find the equation of perpendicular bisector of the line joining the points (1, 1) and (2, 3). 

Solution

Correct option is

2x + 4y – 11 = 0

 

Let P ≡ (1, 1)   and    Q ≡ (2, 3)   

The perpendicular bisector (L) of PQ will pass through R (the midpoint of PQ).  

                

      

  

Now equation of L: slope = –1/2 passing through R (3/2, 2) is:  

                        y – 2 = –1/2(x – 3/2)   

or               2x + 4y – 11 = 0 is the required equation.

SIMILAR QUESTIONS

Q1

Angles made with x-axis by the two lines through the point  (1, 2) and cutting the line x + y = 4 at a distance  from the point (1, 2) are

Q2

If the algebraic sum of the perpendicular distances of a variable line from the points (0, 2), (2, 0) and (1, 1) is zero, then the line always passes through the point

Q3

 be three points. Then the equation of the bisector of angle PQR is

Q4

Find the area of triangle ABC with vertices A (aa2), B (bb2), C (cc2).

Q5

A straight line passes through (2, 3) and the portion of the line intercepted between the axes is bisected at this point. Find its equation

Q6

Find the slope (m), intercepts on X axis, intercept on Y axis of the line 3x+ 2y – 12 = 0. Also trace the line on XY plane.

Q7

Given the triangle A (10, 4), B(–4, 9), C(–2, 1), find the equation of median through B.

Q8

Find the equation of the straight line passing through the points (3, 3) and (7, 6). What is the length of the portion of the line intercepted between the axes of the coordinates.

Q9

Given the triangle with vertices A (–4, 9), B (10, 4), C (–2, –1). Find the equation of the altitude through A.

Q10

Find the coordinates of the foot of the perpendicular from the point (2, 3) on the line y = 3x + 4.