Find the equation of perpendicular bisector of the line joining the points (1, 1) and (2, 3).
2x + 4y – 11 = 0
Let P ≡ (1, 1) and Q ≡ (2, 3)
The perpendicular bisector (L) of PQ will pass through R (the midpoint of PQ).
Now equation of L: slope = –1/2 passing through R (3/2, 2) is:
y – 2 = –1/2(x – 3/2)
or 2x + 4y – 11 = 0 is the required equation.
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