Find the equation of the line perpendicular to 3x + 4y + 1= 0 and passing through (1, 1).
4x – 3y – 1 = 0
Equation of line perpendicular to 3x + 4y + 1 = 0 can be taken as
4x – 3y + k = 0.
(i) Interchange coefficient of x and y
(ii) Reverse the sign between x and y
Now, the line passes through (1, 1):
Hence required equation is:
4x – 3y – 1 = 0.
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