Find The Equation Of The Line Perpendicular To 3x + 4y + 1= 0 And Passing Through (1, 1).

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Question

Find the equation of the line perpendicular to 3x + 4y + 1= 0 and passing through (1, 1).

easy

Solution

Correct option is

4x – 3y – 1 = 0

Equation of line perpendicular to 3x + 4y + 1 = 0 can be taken as

4x – 3y + k = 0.

(i) Interchange coefficient of x and y

(ii) Reverse the sign between x and y

Now, the line passes through (1, 1):

Hence required equation is:

4x – 3y – 1 = 0.

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