## Question

### Solution

Correct option is

4x – 3y – 1 = 0

Equation of line perpendicular to 3x + 4y + 1 = 0 can be taken as

4x – 3y + k = 0.

(i) Interchange coefficient of x and y

(ii) Reverse the sign between x and y

Now, the line passes through (1, 1): Hence required equation is:

4x – 3y – 1 = 0.

#### SIMILAR QUESTIONS

Q1

Find the area of triangle ABC with vertices A (aa2), B (bb2), C (cc2).

Q2

A straight line passes through (2, 3) and the portion of the line intercepted between the axes is bisected at this point. Find its equation

Q3

Find the slope (m), intercepts on X axis, intercept on Y axis of the line 3x+ 2y – 12 = 0. Also trace the line on XY plane.

Q4

Given the triangle A (10, 4), B(–4, 9), C(–2, 1), find the equation of median through B.

Q5

Find the equation of the straight line passing through the points (3, 3) and (7, 6). What is the length of the portion of the line intercepted between the axes of the coordinates.

Q6

Given the triangle with vertices A (–4, 9), B (10, 4), C (–2, –1). Find the equation of the altitude through A.

Q7

Find the equation of perpendicular bisector of the line joining the points (1, 1) and (2, 3).

Q8

Find the coordinates of the foot of the perpendicular from the point (2, 3) on the line y = 3x + 4.

Q9

Find the equation of the line passing through (ab) and parallel to px +qy + 1 = 0.

Q10

Find the distance of line h (x + h) + k (y + k) = 0 from the origin.