If A (cos α, Sin α), B (sin α, –cos α), C (1, 2) Are The Vertices Of A ΔABC, Then As α Varies The Locus Of Its Centroid Is:

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Question

If A (cos α, sin α), B (sin α, –cos α), C (1, 2) are the vertices of a ΔABC, then as α varies the locus of its centroid is:

Solution

Correct option is

3 (x2 + y2) – 2x – 4y + 1 = 0

Suppose co-ordinate of centroid is (x1y1)

   

    

  

Square and add (i) and (ii)

  

Replace x1 by x and y1 by y.     

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