﻿ For a fixed positive integer n, let D =                     : Kaysons Education

# For A Fixed Positive Integer N, Let D =

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## Question

### Solution

Correct option is

– 64

Take (n – 1)!, (n + 1)!, (n + 3)! Common from R1, R2, R3 respectively

Making two zeros in column 1 by applying R3 – R2 and R2 – R1, we have

= 8 [4n + 6 – 4n – 14] = 8 [– 8] = – 64.

#### SIMILAR QUESTIONS

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Q2
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Q10

Evaluate the determinant without expansion as far as possible.