a = 1, c = 1 & b = 2
This limit exists if a – b + c = 0, a – c = 0 and is equal to 2 and if (a + b + c)/2 = 2, i.e. a + b + c = 4.
Solving these equations, we get a = 1, c = 1, and b = 2.
We can apply L’ Hospital rule also to get the required conclusion.
The value which should be assigned to f at x = a so that it is continuous everywhere is
The number of points at which the function f(x) = 1/log |x| is discontinuous is
The value of a for which tends to a finite limit as is
where g is a continuous function. Then exists if
The value of is
Let Then the value of f (0) so that the function fis continuous is
is continuous at x = 0, then