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## Question

### Solution

Correct option is

a = 1, c = 1 & b = 2

We have

This limit exists if – b + c = 0, a – c = 0 and is equal to 2 and if (a + b + c)/2 = 2, i.e. a + b + c = 4.

Solving these equations, we get a = 1, c = 1, and b = 2.

We can apply L’ Hospital rule also to get the required conclusion.

#### SIMILAR QUESTIONS

Q1

Let

The value which should be assigned to f at x = a so that it is continuous everywhere is

Q2

The number of points at which the function f(x) = 1/log |x| is discontinuous is

Q3

For  R,

Q4

The value of a for which  tends to a finite limit as  is

Q5

Let

where g is a continuous function. Then  exists if

Q6

The value of  is

Q7

Let Then the value of f (0) so that the function fis continuous is

Q10

is continuous at x = 0, then