: Kaysons Education

Why Kaysons ?

Video lectures

Access over 500+ hours of video lectures 24*7, covering complete syllabus for JEE preparation.

Online Support

Practice over 30000+ questions starting from basic level to JEE advance level.

Live Doubt Clearing Session

Ask your doubts live everyday Join our live doubt clearing session conducted by our experts.

National Mock Tests

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

Organized Learning

Proper planning to complete syllabus is the key to get a decent rank in JEE.

Test Series/Daily assignments

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

SPEAK TO COUNSELLOR ? CLICK HERE

Download JEE Question paper & Solution Download JEE Important questions Download Complete syllabus of Maths, Physics, Chemistry

Question

easy

Solution

Correct option is

a = 1, c = 1 & b = 2

We have

This limit exists if a – b + c = 0, a – c = 0 and is equal to 2 and if (a + b + c)/2 = 2, i.e. a + b + c = 4.

Solving these equations, we get a = 1, c = 1, and b = 2.

We can apply L’ Hospital rule also to get the required conclusion.

Download JEE Question paper & Solution Download JEE Important questions Download Complete syllabus of Maths, Physics, Chemistry

SIMILAR QUESTIONS

Q1

Let

The value which should be assigned to f at x = a so that it is continuous everywhere is

medium View solution

Q2

The number of points at which the function f(x) = 1/log |x| is discontinuous is

easy View solution

Q3

For R,

easy View solution

Q4

The value of a for which tends to a finite limit as is

easy View solution

Q5

Let

where g is a continuous function. Then exists if

easy View solution

Q6

The value of is

medium View solution

Q7

Let Then the value of f (0) so that the function fis continuous is

easy View solution

Q8

easy View solution

Q9

easy View solution

Q10

is continuous at x = 0, then

diffcult View solution