﻿ The value of y’’ (1) if x3 – 2x2y2 + 5x + y – 5 = 0 when y(1) = 1, is equal to : Kaysons Education

# The Value Of y’’ (1) If x3 – 2x2y2 + 5x + y – 5 = 0 When y(1) = 1, Is Equal To

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## Question

### Solution

Correct option is

Differentiating the given expression, we get

3x2 – 4xy2 – 4x2yy’ + 5 + y’ = 0

Putting x = 1, we have

3 – 4.1.1 – 4.1.1y’ (1) + 5 + y’(1) = 0

⇒               4 – 3y’(1) = 0 ⇒ y’(1) = 4/3

Differentiating again, we have

Putting x – 1, y = 1 and y’(1) = 4/3, we get

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